Integrand size = 28, antiderivative size = 125 \[ \int \frac {(d+e x)^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {(b d-a e)^2}{4 b^3 (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {2 e (b d-a e)}{3 b^3 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {e^2}{2 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Time = 0.05 (sec) , antiderivative size = 125, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {660, 45} \[ \int \frac {(d+e x)^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {2 e (b d-a e)}{3 b^3 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(b d-a e)^2}{4 b^3 (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {e^2}{2 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Rule 45
Rule 660
Rubi steps \begin{align*} \text {integral}& = \frac {\left (b^4 \left (a b+b^2 x\right )\right ) \int \frac {(d+e x)^2}{\left (a b+b^2 x\right )^5} \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}} \\ & = \frac {\left (b^4 \left (a b+b^2 x\right )\right ) \int \left (\frac {(b d-a e)^2}{b^7 (a+b x)^5}+\frac {2 e (b d-a e)}{b^7 (a+b x)^4}+\frac {e^2}{b^7 (a+b x)^3}\right ) \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}} \\ & = -\frac {(b d-a e)^2}{4 b^3 (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {2 e (b d-a e)}{3 b^3 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {e^2}{2 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(417\) vs. \(2(125)=250\).
Time = 1.30 (sec) , antiderivative size = 417, normalized size of antiderivative = 3.34 \[ \int \frac {(d+e x)^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {x \left (6 a^2 b^6 d e x^7-3 a^4 \sqrt {a^2} b^2 x^2 \sqrt {(a+b x)^2} \left (2 d^2+2 d e x+e^2 x^2\right )+4 a^8 \left (3 d^2+3 d e x+e^2 x^2\right )+a^7 b x \left (18 d^2+8 d e x+e^2 x^2\right )-3 \sqrt {a^2} b^4 x^4 \sqrt {(a+b x)^2} \left (b^2 d^2 x^2+a^2 (d+e x)^2\right )+3 a^3 b^3 x^3 \left (-b^2 e^2 x^4+\sqrt {a^2} \sqrt {(a+b x)^2} (d+e x)^2\right )+3 a b^5 d x^5 \left (-b^2 d x^2+\sqrt {a^2} \sqrt {(a+b x)^2} (d+2 e x)\right )-2 a^6 \left (-b^2 d x^2 (6 d+e x)+2 \sqrt {a^2} \sqrt {(a+b x)^2} \left (3 d^2+3 d e x+e^2 x^2\right )\right )+a^5 \left (3 b^3 d^2 x^3+\sqrt {a^2} b x \sqrt {(a+b x)^2} \left (-6 d^2+4 d e x+3 e^2 x^2\right )\right )\right )}{12 a^8 (a+b x)^3 \left (\sqrt {a^2} b x+a \left (\sqrt {a^2}-\sqrt {(a+b x)^2}\right )\right )} \]
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Time = 2.46 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.55
method | result | size |
gosper | \(-\frac {\left (b x +a \right ) \left (6 x^{2} b^{2} e^{2}+4 x a b \,e^{2}+8 b^{2} d e x +a^{2} e^{2}+2 a b d e +3 b^{2} d^{2}\right )}{12 b^{3} \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}\) | \(69\) |
default | \(-\frac {\left (b x +a \right ) \left (6 x^{2} b^{2} e^{2}+4 x a b \,e^{2}+8 b^{2} d e x +a^{2} e^{2}+2 a b d e +3 b^{2} d^{2}\right )}{12 b^{3} \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}\) | \(69\) |
risch | \(\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (-\frac {e^{2} x^{2}}{2 b}-\frac {e \left (a e +2 b d \right ) x}{3 b^{2}}-\frac {a^{2} e^{2}+2 a b d e +3 b^{2} d^{2}}{12 b^{3}}\right )}{\left (b x +a \right )^{5}}\) | \(72\) |
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Time = 0.26 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.78 \[ \int \frac {(d+e x)^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {6 \, b^{2} e^{2} x^{2} + 3 \, b^{2} d^{2} + 2 \, a b d e + a^{2} e^{2} + 4 \, {\left (2 \, b^{2} d e + a b e^{2}\right )} x}{12 \, {\left (b^{7} x^{4} + 4 \, a b^{6} x^{3} + 6 \, a^{2} b^{5} x^{2} + 4 \, a^{3} b^{4} x + a^{4} b^{3}\right )}} \]
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\[ \int \frac {(d+e x)^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\int \frac {\left (d + e x\right )^{2}}{\left (\left (a + b x\right )^{2}\right )^{\frac {5}{2}}}\, dx \]
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Time = 0.21 (sec) , antiderivative size = 115, normalized size of antiderivative = 0.92 \[ \int \frac {(d+e x)^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {2 \, d e}{3 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} b^{2}} - \frac {e^{2}}{2 \, b^{5} {\left (x + \frac {a}{b}\right )}^{2}} + \frac {2 \, a e^{2}}{3 \, b^{6} {\left (x + \frac {a}{b}\right )}^{3}} - \frac {d^{2}}{4 \, b^{5} {\left (x + \frac {a}{b}\right )}^{4}} + \frac {a d e}{2 \, b^{6} {\left (x + \frac {a}{b}\right )}^{4}} - \frac {a^{2} e^{2}}{4 \, b^{7} {\left (x + \frac {a}{b}\right )}^{4}} \]
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Time = 0.26 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.55 \[ \int \frac {(d+e x)^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {6 \, b^{2} e^{2} x^{2} + 8 \, b^{2} d e x + 4 \, a b e^{2} x + 3 \, b^{2} d^{2} + 2 \, a b d e + a^{2} e^{2}}{12 \, {\left (b x + a\right )}^{4} b^{3} \mathrm {sgn}\left (b x + a\right )} \]
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Time = 9.63 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.63 \[ \int \frac {(d+e x)^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {\sqrt {a^2+2\,a\,b\,x+b^2\,x^2}\,\left (a^2\,e^2+2\,a\,b\,d\,e+4\,a\,b\,e^2\,x+3\,b^2\,d^2+8\,b^2\,d\,e\,x+6\,b^2\,e^2\,x^2\right )}{12\,b^3\,{\left (a+b\,x\right )}^5} \]
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